Three forces are applied to a bracket as shown. Determine the total (equivalent) force applied to the barcket

Problem:
        
% Three forces are applied to a bracket as shown. Determine the total (equivalent) force applied to the barcket%


%IN COMMAND WINDOW

>> F1m=400;F2m=500;F3m=700;

>> Th1=-20*pi/180;Th2=30*pi/180;Th3=143*pi/180;

>> F1=F1m*[cos(Th1) sin(Th1)]

F1 =

  375.8770 -136.8081

>> F2=F2m*[cos(Th2) sin(Th2)]

F2 =

  433.0127  250.0000

>> F3=F3m*[cos(Th3) sin(Th3)]

F3 =

 -559.0449  421.2705

>> Ftotal=F1+F2+F3

Ftotal =

  249.8449  534.4625

>> Ftotalm=sqrt(Ftotal(1)^2+Ftotal(2)^2)

Ftotalm =

  589.9768

>> Th=(180/pi)*tan(Ftotal(2)/Ftotal(1))

Th =

  -89.7088